findLastKeyWithVal
findLastKeyWithVal
(value: any) => (sequence: Sequence) => number | undefined
Find the last index which has
value
.const findLastKeyOfA = findLastKeyWithVal('a') findLastKeyOfA(['a', 'b', 'a']) // is 2 findLastKeyOfA(['b', 'c']) // is undefined findLastKeyOfA('aba') // is 2
const findLastKeyOfA = findLastKeyWithVal('a') findLastKeyOfA(['a', 'b', 'a']) // is 2 findLastKeyOfA(['b', 'c']) // is undefined findLastKeyOfA('aba') // is 2
const findLastKeyOfA = findLastKeyWithVal('a') findLastKeyOfA(['a', 'b', 'a']) // is 2 findLastKeyOfA(['b', 'c']) // is undefined findLastKeyOfA('aba') // is 2
const findLastKeyOfA = findLastKeyWithVal('a') findLastKeyOfA(['a', 'b', 'a']) // is 2 findLastKeyOfA(['b', 'c']) // is undefined findLastKeyOfA('aba') // is 2
Sometimes we want to find the last index to a value. Below, Chris starts a weightlifting program by seeing how many reps he can lift per level. Let's find the highest level where he can only lift one rep.
const repsPerWeightLevel = [12, 12, 10, 8, 6, 3, 1, 1, 0] const findOneRepMax = findLastKeyWithVal(1) const maxWeightLevel = findOneRepMax(repsPerWeightLevel) console.log(maxWeightLevel) // is 7
const repsPerWeightLevel = [12, 12, 10, 8, 6, 3, 1, 1, 0] const findOneRepMax = findLastKeyWithVal(1) const maxWeightLevel = findOneRepMax(repsPerWeightLevel) console.log(maxWeightLevel) // is 7
const repsPerWeightLevel = [ 12, 12, 10, 8, 6, 3, 1, 1, 0, ] const findOneRepMax = findLastKeyWithVal(1) const maxWeightLevel = findOneRepMax( repsPerWeightLevel ) console.log(maxWeightLevel) // is 7
const repsPerWeightLevel = [ 12, 12, 10, 8, 6, 3, 1, 1, 0, ] const findOneRepMax = findLastKeyWithVal(1) const maxWeightLevel = findOneRepMax( repsPerWeightLevel ) console.log(maxWeightLevel) // is 7